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数学の楽園＞

中１立体図形＞

Ｉ立体の体積

あまった図形置き場

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\begin{xy} (0,40)*{正３角錐}="A", (0,-3)*{3}="A", (-5,8)*{3}="A", {(0,8) \ar @{.}(-12,0)}, {(0,8) \ar @{.}(12,0)}, {(12,0) \ar @{-}(-12,0)}, {(0,8) \ar @{.}(0,35)}, {(12,0) \ar @{-}(0,35)}, {(-12,0) \ar @{-}(0,35)}, \end{xy}

\begin{xy} (0,40)*{正３角錐}="A", (0,-3)*{3}="A", (-5,8)*{3}="A", {(0,8) \ar @{.}(-12,0)}, {(0,8) \ar @{.}(12,0)}, {(12,0) \ar @{-}(-12,0)}, {(0,8) \ar @{.}(0,35)}, {(12,0) \ar @{-}(0,35)}, {(-12,0) \ar @{-}(0,35)}, \end{xy}

\begin{xy} (0,40)*{正３角錐}="A", (0,-3)*{3}="A", (-5,8)*{3}="A", {(0,8) \ar @{.}(-12,0)}, {(0,8) \ar @{.}(12,0)}, {(12,0) \ar @{-}(-12,0)}, {(0,8) \ar @{.}(0,35)}, {(12,0) \ar @{-}(0,35)}, {(-12,0) \ar @{-}(0,35)}, \end{xy}

\begin{xy} (0,40)*{正３角錐}="A", (0,-3)*{3}="A", (-5,8)*{3}="A", {(0,8) \ar @{.}(-12,0)}, {(0,8) \ar @{.}(12,0)}, {(12,0) \ar @{-}(-12,0)}, {(0,8) \ar @{.}(0,35)}, {(12,0) \ar @{-}(0,35)}, {(-12,0) \ar @{-}(0,35)}, \end{xy}